УМОЛЯЮ ПОМОГИТЕ ПОЖАЛУЙСТА! Очень срочное и важное...

Changes in the state of a system are produced by interactions with the environment through heat and work, which are two different modes of energy transfer. To find the work we must know the path. also for , , so the work done by the system is. or in terms of the specific volume and the system massThe expansion is isentropic (How does that differ from an adiabatic expansion? I thought the condition that dS = 0 constrained a gas to a unique trajectory Now consider the passage of a small amount of gas from one side to the other. On side 1, the rest of the gas does work $p_1 V_1$ to push the...What do your clothes really say about you? but now it is possible to do so on a more personal level, as people use their outfits as a form of self-_. Even when there is nothing obvious like blue hair or a shredded shirt.A gas expands from 263 mL to 939 mL at a constant temperature. How many moles of sugar was added to 82.90 g of ethanol to change the freezing point of ethanol by 2.750 c? How do I decide whether to use a Heck or Suzuki reaction? ?D. Folders do not maximize or minimize. 3. According to the passage, what does the pointer NOT do? D It expands the functionality of a web. Check the FAQs to find out about tine company. 4 . Fill in the blanks with the correct words and phrases from the word bank.

Why does Joule-Thomson expansion of a gas do no (external) work?

As the gas proceeds from state 1 to state 2, it is heated at constant pressure. ANSWER: dW = pdV Hint 2. Doing the integration To find the work done by the gas as it expands from state 1 to state 2, multiply the gas pressure by the change in volume between states 1 and 2. When you do this, what...If the gas is ideal and the expansion is isothermal, then P = nRT/V and the equation can be integrated with respect to V. If the process is adiabatic, the equation P1V1^g = PV^g can be used to substitue P in terms of conditions of State 1.Key concepts Chemistry States of matter Gases Energy Temperature Introduction Have you ever baked—or purchased—a loaf of bread, muffins If so, you have appreciated the work of expanding gases! They are everywhere—from the kitchen to the cosmos. You've sampled their pleasures every......one mole of a gas is expanded from state A to state B? a) When the gas expands from state A to state B, the surroundings are doing work on the system. b) Two metals of equal mass with different heat capacities are subjected to the same amount of heat. Which undergoes the smallest change in...

ЕГЭ2021, английский язык: задания, ответы, решения.

Every country, from the United States to China, must participate, and every industry, from oil and gas to tech How long has this Great Reset been in the works? The answers to these questions can help us understand the In the book, Schwab expands upon the initial announcement of The Great Reset.We could, however, move from State 1 to State 2 by holding the pressure constant and increasing the volume by heating the gas using Charles' law. If we then remove the weights, holding a constant volume, we proceed on to State 2. The work done in this process is shown by the yellow shaded area.The first law of thermodynamics can be simply stated as follows: during an interaction between a The expansion and compression work is often called moving boundary work, or simply boundary Note: a gas can follow several different paths from state 1 to 2, and each path will have a different...We consider the First Law of Thermodynamics applied to stationary closed systems as a conservation of energy principle. Thus energy is transferred between the system and the surroundings in the form of heat and work, resulting in a change of internal energy of the system. Internal energy change can be...We know that from state 1 to state 2, the gas undergoes a polytropic process, where we have PV raised to the power n, is a constant value. Expansion, work out. And so that is a positive value. Now we're asked to find the total work for both steps, so all we do is add these two together.

(*1*)Concepts and explanation why

(*1*)The main thought used to remedy this problem is work done for a thermodynamic process and perfect gas equation.

(*1*)Find out the space below the P-V curve and find out the work done on the gas from state 1 to state 2, state 2 to state 3, state 3 to sate Four and state 4 to state 1. Add all the values of work done i.e. from and find the general work done on the gas throughout one cycle.

(*1*)For the final part, use supreme gas equation and find temperature for state 3.

(*1*)Fundamentals

(*1*)The equation of state for a perfect gas is given as follows:

(*1*)

(*1*)Here, P is the power, V is the volume, n is the choice of moles, R is the common gas constant and T is the temperature of splendid gas.

(*1*)The work done by gas for o thermodynamic procedure is calculated as:

(*1*)

(*1*)The quantity of work done by gas is determined by initial and ultimate state and the path additionally.

(*1*)(A)

(*1*)The work done on the gas from state 1 to state 2 is calculated as:

(*1*)

(*1*)Substitute for , for and for in the above equation.

(*1*)

(*1*)(B)

(*1*)The work done on the gas from state 2 to state Three is calculated as:

(*1*)

(*1*)The volume of the gas is continuing throughout the process from state 2 to state 3. Hence, replace 0 for dV.

(*1*)

(*1*)Therefore, the work done on the gas as it cools from state 2 to state Three is 0.

(*1*)(C)

(*1*)The work done on the gas from state 3 to state Four is calculated as:

(*1*)

(*1*)Substitute for , for and for in the above equation.

(*1*)

(*1*)(D)

(*1*)The work done on the gas from state 4 to state 1 is calculated as:

(*1*)

(*1*)The volume of the gas is continuing all through the procedure from state 4 to state 1. Hence, exchange Zero for dV.

(*1*)

(*1*)Therefore, the work done on the gas as it cools from state 4 to state 1 is 0.

(*1*)(E)

(*1*)The work done on the gas all over one cycle is:

(*1*)

(*1*)Substitute for, for, Zero for and.

(*1*)

(*1*)(F)

(*1*)The temperature when the gas is in state 1 is calculated as:

(*1*)

(*1*)Substitute for and for in the above equation.

(*1*)

(*1*)The temperature when the gas is in state 3 is calculated as:

(*1*)

(*1*)Substitute for and for in the above equation.

(*1*)

(*1*)Re-arrange equation for the price of nR.

(*1*)

(*1*)Use in equation.

(*1*)

Ans: Part A(*1*)The work done on the gas as it expands from state 1 to state 2 is .

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